一、gojsonp简介

二、常规用法
https://github.com/thedevsaddam/gojsonq

三、经典用法
1、取出json array符合条件的一组元素的某一个值

[
    {
        "showName":"提交申请",
        "showNameEn":"Submit",
        "remark":""
    },
    {
        "showName":"审核",
        "showNameEn":"managerApproval",
        "remark":"Disagree"
    }
]

取showNameEn为managerApproval所在remark内容

package main

import (
	"fmt"

	"github.com/thedevsaddam/gojsonq"
)

func main() {
	const json = `[{"showName":"提交申请","showNameEn":"Submit","remark":""},{"showName":"审核","showNameEn":"managerApproval", "remark":"Disagree"}]`

	infos := gojsonq.New().JSONString(json).Where("showNameEn", "=", "managerApproval").Get()

	var interfaceSlice []interface{} = make([]interface{}, 0)
	interfaceSlice := infos.([]interface{})

	info := interfaceSlice[0].(map[string]interface{})
	
	fmt.Printf("%#v", info["remark"])
}

参考：
Golang 从 Json 串中快速取出需要的字段【CSDN的文章，不用细看】